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QuantumInfo.ForMathlib.HayataGroup.TraceInequality.JensenOperatorInequalityIImpIV

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instance

Continuous functional calculus for normal elements in B(H)×B(H)\mathcal{B}(\mathcal{H}) \times \mathcal{B}(\mathcal{H}) over C\mathbb{C}

Let H\mathcal{H} be a complex inner product space and let B(H)\mathcal{B}(\mathcal{H}) denote the space of bounded linear operators on H\mathcal{H}. The product space B(H)×B(H)\mathcal{B}(\mathcal{H}) \times \mathcal{B}(\mathcal{H}) admits a continuous functional calculus over the complex numbers C\mathbb{C} for pairs of normal operators (elements satisfying xx=xxx^*x = xx^*).

instance

Existence of Continuous Functional Calculus for Self-Adjoint Elements in B(H)×B(H)\mathcal{B}(\mathcal{H}) \times \mathcal{B}(\mathcal{H}) over R\mathbb{R}

Let H\mathcal{H} be a complex inner product space and let B(H)\mathcal{B}(\mathcal{H}) denote the space of bounded linear operators on H\mathcal{H}. Then the product space B(H)×B(H)\mathcal{B}(\mathcal{H}) \times \mathcal{B}(\mathcal{H}) admits a continuous functional calculus over R\mathbb{R} for self-adjoint elements.

instance

B(HH)\mathcal{B}(\mathcal{H} \oplus \mathcal{H}) is a Non-negative Spectrum Class

Let H\mathcal{H} be a complex Hilbert space and let HH\mathcal{H} \oplus \mathcal{H} denote the two-fold Hilbert sum (the 2\ell^2 direct sum of two copies of H\mathcal{H}). The algebra of bounded linear operators on this space, denoted B(HH)\mathcal{B}(\mathcal{H} \oplus \mathcal{H}), is a non-negative spectrum class over R\mathbb{R}. This implies that for any self-adjoint operator TB(HH)T \in \mathcal{B}(\mathcal{H} \oplus \mathcal{H}), its spectrum σ(T)\sigma(T) is a subset of [0,)[0, \infty) if and only if TT is a non-negative operator.

definition

Jensen's operator inequality f(XAX)Xf(A)Xf(X^* A X) \leq X^* f(A) X for positive AA and contractions XX

Let H\mathcal{H} be a complex Hilbert space and B(H)\mathcal{B}(\mathcal{H}) be the algebra of bounded linear operators on H\mathcal{H}. For a function f:RRf: \mathbb{R} \to \mathbb{R}, this condition states that for every self-adjoint operator AB(H)A \in \mathcal{B}(\mathcal{H}) with non-negative spectrum σ(A)[0,)\sigma(A) \subseteq [0, \infty) and for every operator XB(H)X \in \mathcal{B}(\mathcal{H}) with operator norm X1\|X\| \leq 1, the following inequality holds in the Loewner order: f(XAX)Xf(A)Xf(X^* A X) \leq X^* f(A) X where f()f(\cdot) is the operator defined via the continuous functional calculus.

definition

Operator convexity of ff and f(0)0f(0) \le 0

Let H\mathcal{H} be a complex Hilbert space and B(H)\mathcal{B}(\mathcal{H}) be the algebra of bounded linear operators on H\mathcal{H}. For a function f:RRf: \mathbb{R} \to \mathbb{R}, this property (Condition (i) in Theorem 2.5.2) holds if ff is operator convex on B(H)\mathcal{B}(\mathcal{H}) and f(0)0f(0) \le 0. Specifically, ff is operator convex if for any two self-adjoint operators A,BB(H)A, B \in \mathcal{B}(\mathcal{H}) and any t[0,1]t \in [0, 1], the inequality f((1t)A+tB)(1t)f(A)+tf(B)f((1 - t)A + tB) \le (1 - t)f(A) + tf(B) holds in the Loewner order.

definition

Operator convexity of ff on all Hilbert spaces and f(0)0f(0) \leq 0

For a function f:RRf: \mathbb{R} \to \mathbb{R}, this property holds if f(0)0f(0) \leq 0 and ff is operator convex on all non-trivial complex Hilbert spaces H\mathcal{H}. Specifically, for every such Hilbert space H\mathcal{H}, given any two bounded self-adjoint operators A,BB(H)A, B \in \mathcal{B}(\mathcal{H}) and any scalar t[0,1]t \in [0, 1], the following inequality holds in the Loewner partial order: f((1t)A+tB)(1t)f(A)+tf(B)f((1 - t)A + tB) \leq (1 - t)f(A) + tf(B) where the function ff is applied to the operators via the continuous functional calculus.

definition

Operator convexity of ff on [0,)[0, \infty) and f(0)0f(0) \le 0 for all Hilbert spaces

Let f:RRf: \mathbb{R} \to \mathbb{R} be a real-valued function. This property (a localized version of Condition (i) from the Jensen operator inequality theorem) holds if ff satisfies the following conditions: 1. ff is operator convex on the interval [0,)[0, \infty) for all non-trivial complex Hilbert spaces H\mathcal{H}. Specifically, for any such H\mathcal{H}, for all self-adjoint operators A,BB(H)A, B \in \mathcal{B}(\mathcal{H}) whose spectra σ(A),σ(B)\sigma(A), \sigma(B) are contained in [0,)[0, \infty), and for any t[0,1]t \in [0, 1], the inequality f((1t)A+tB)(1t)f(A)+tf(B)f((1 - t)A + tB) \leq (1 - t)f(A) + tf(B) holds in the Löwner order. 2. ff is continuous on [0,)[0, \infty). 3. f(0)0f(0) \le 0.

definition

Operator Jensen inequality f(XAX+YBY)Xf(A)X+Yf(B)Yf(X^* A X + Y^* B Y) \le X^* f(A) X + Y^* f(B) Y

For a function f:RRf: \mathbb{R} \to \mathbb{R}, this property (referred to as Condition (v) in Theorem 2.5.2) states that for any complex Hilbert space H\mathcal{H} and any bounded self-adjoint operators A,BB(H)A, B \in \mathcal{B}(\mathcal{H}) whose spectra are contained in [0,)[0, \infty), and for any bounded linear operators X,YB(H)X, Y \in \mathcal{B}(\mathcal{H}) satisfying the contractive condition XX+YYIX^* X + Y^* Y \le I, the following operator inequality holds: f(XAX+YBY)Xf(A)X+Yf(B)Yf(X^* A X + Y^* B Y) \le X^* f(A) X + Y^* f(B) Y where f()f(\cdot) denotes the operator obtained via the continuous functional calculus.

theorem

Operator Convexity on [0,)[0, \infty) with f(0)0f(0) \leq 0 implies Jensen's Operator Inequality for Contractions

Let f:RRf: \mathbb{R} \to \mathbb{R} be a real-valued function. Suppose that for all non-trivial complex Hilbert spaces, ff is operator convex on [0,)[0, \infty), continuous on [0,)[0, \infty), and satisfies f(0)0f(0) \leq 0. Then, for any complex Hilbert space H\mathcal{H}, the following holds: for every self-adjoint operator AB(H)A \in \mathcal{B}(\mathcal{H}) with spectrum σ(A)[0,)\sigma(A) \subseteq [0, \infty) and for every operator XB(H)X \in \mathcal{B}(\mathcal{H}) with operator norm X1\|X\| \leq 1, the inequality f(XAX)Xf(A)Xf(X^* A X) \leq X^* f(A) X holds in the Löwner order, where f()f(\cdot) is defined via the continuous functional calculus.

theorem

Operator Convexity with f(0)0f(0) \le 0 Implies f(XAX)Xf(A)Xf(X^*AX) \le X^*f(A)X for Contractions XX

Let f:RRf: \mathbb{R} \to \mathbb{R} be a function such that f(0)0f(0) \leq 0. Suppose ff is operator convex on all complex Hilbert spaces H\mathcal{H}; that is, for any A,BB(H)A, B \in \mathcal{B}(\mathcal{H}) self-adjoint and t[0,1]t \in [0, 1], the inequality f((1t)A+tB)(1t)f(A)+tf(B)f((1 - t)A + tB) \leq (1 - t)f(A) + tf(B) holds in the Loewner partial order (where ff is defined via the continuous functional calculus). Then, ff satisfies Jensen's operator inequality for contractions: for any complex Hilbert space H\mathcal{H}, any self-adjoint operator AB(H)A \in \mathcal{B}(\mathcal{H}) with spectrum σ(A)[0,)\sigma(A) \subseteq [0, \infty), and any operator XB(H)X \in \mathcal{B}(\mathcal{H}) with operator norm X1\|X\| \leq 1, it holds that f(XAX)Xf(A)Xf(X^* A X) \leq X^* f(A) X.