Physlib

PhyslibAlpha.ProbabilisticTheory.Measurement.Pushforward

Pushing an effect-valued measure forward along a channel

i. Overview

A channel sends effects to effects. Applying a normal channel `φ : Channel E F` to every effect of an effect-valued measure `μ` on `E` therefore gives one, `μ.map φ`, on `F`, with the same outcomes.

ii. Key results

  • `EffectValuedMeasure.map` : pushing an effect-valued measure forward along a normal channel.

iii. Table of contents

  • A. Channels send effects to effects
  • B. Pushing an effect-valued measure forward

A. Channels send effects to effects

B. Pushing an effect-valued measure forward

6 declarations

definition

The effect ϕ(e)\phi(e) for a channel ϕ\phi and effect ee

Given a channel ϕ:E→F\phi : E \to F (defined as a unital positive linear map) and an effect ee in the space EE (an element satisfying 0≤e≤10 \le e \le 1), this definition represents the image ϕ(e)\phi(e) as an effect in the space FF. Because ϕ\phi is a positive linear map and ϕ(1)=1\phi(1) = 1, the result ϕ(e)\phi(e) is guaranteed to satisfy the bounds 0≤ϕ(e)≤10 \le \phi(e) \le 1.

theorem

(ϕ.mapEffect e:F)=ϕe(\phi.\text{mapEffect } e : F) = \phi e

Let EE and FF be spaces and ϕ:E→F\phi : E \to F be a channel (a unital positive linear map). For any effect e∈Ee \in E (an element satisfying 0≤e≤10 \le e \le 1), the image of ee under ϕ\phi viewed as an effect in FF is equal to the application of the map ϕ\phi to ee as an element of the underlying space FF. That is, (ϕ.mapEffect(e):F)=ϕ(e)(\phi.\text{mapEffect}(e) : F) = \phi(e).

theorem

ϕ(0)=0\phi(0) = 0 for a quantum channel ϕ\phi

Let EE and FF be order unit spaces, and let ϕ:E→F\phi : E \to F be a quantum channel (a unital positive linear map). For the zero effect 0∈E0 \in E (the zero element of the space, which belongs to the interval [0,1][0, 1]), its image under the map ϕ\phi is the zero effect in FF. That is, ϕ(0)=0\phi(0) = 0.

theorem

ϕ(1)=1\phi(1) = 1 for any channel ϕ\phi

For any channel ϕ:E→F\phi : E \to F between order unit spaces EE and FF, the image of the unit effect 1∈E1 \in E under the map ϕ\phi is the unit effect 1∈F1 \in F, which can be written as ϕ(1)=1\phi(1) = 1.

definition

Push-forward of an effect-valued measure μ\mu along a channel ϕ\phi

Let Ω\Omega be a measurable space and E,FE, F be ordered vector spaces. Given an effect-valued measure μ\mu on Ω\Omega with values in EE, and a normal channel ϕ:E→F\phi : E \to F (a unital positive linear map that preserves the suprema of directed sets), the push-forward ϕ∘μ\phi \circ \mu is an effect-valued measure on Ω\Omega taking values in FF. For any measurable set s⊆Ωs \subseteq \Omega, the measure is defined by applying the channel to the effect assigned by the original measure, i.e., (ϕ∘μ)(s)=ϕ(μ(s))(\phi \circ \mu)(s) = \phi(\mu(s)).

theorem

Evaluation of a push-forward effect-valued measure (μ.map ϕ)(s)=ϕ(μ(s))(\mu.\text{map } \phi)(s) = \phi(\mu(s))

Let Ω\Omega be a measurable space and E,FE, F be ordered vector spaces. Let μ\mu be an effect-valued measure on Ω\Omega taking values in EE, and let ϕ:E→F\phi: E \to F be a normal channel (a unital positive linear map that preserves the suprema of directed sets). For any measurable set s⊆Ωs \subseteq \Omega, the value of the push-forward effect-valued measure μ.map ϕ\mu.\text{map } \phi at ss is equal to the image of the effect μ(s)\mu(s) under the channel ϕ\phi: (μ.map ϕ)(s)=ϕ(μ(s)) (\mu.\text{map } \phi)(s) = \phi(\mu(s)) where both sides are viewed as elements of the space FF.