Physlib.SpaceAndTime.Space.Integrals.NormPow
Integrability of norm powers on subsets of Space
i. Overview
This module contains results on the integrability of `x ↦ ‖x‖ᵖ` for real exponents `p` on subsets of `Space d`.
The integrability of `x ↦ ‖x‖ᵖ` on `ball 0 b` and `(ball 0 b)ᶜ` follows from the 1d results `integrableOn_Ioo_rpow_iff` and `integrableOn_Ioi_rpow_iff` after changing to spherical coordinates.
ii. Key results
- `integrableOn_norm_rpow_iff_of_isBounded_nhds`: Necessary and sufficient condition for integrability on a set `s` which is a bounded neighborhood of the origin. - `integrableOn_norm_rpow_of_isBounded_compl_nhds`: Integrability for all bounded sets `s` with `0 ∉ closure s`. - `integrableOn_norm_rpow_of_compl_nhds`: A sufficient condition for integrability on `s` with `0 ∉ closure s`.
iii. Table of contents
iv. References
6 declarations
is integrable on iff
Let be a -dimensional real inner product space equipped with the Euclidean norm . For any positive integer , positive radius , and exponent , the function is integrable on the open ball if and only if .
is integrable on
For a positive natural number and the -dimensional real inner product space , let be a positive real number and be a real exponent. The function is integrable on the complement of the ball centered at the origin with radius , , if and only if .
is integrable on the shell
Let be a -dimensional real inner product space. For any real number and any real numbers and , the function is integrable on the shell defined by .
is integrable on a bounded neighborhood of
Let be a -dimensional real inner product space with dimension . Let be a bounded set that is also a neighborhood of the origin. For any real exponent , the function is integrable on if and only if , where denotes the Euclidean norm on .
is integrable on bounded sets away from the origin
Let be a -dimensional real inner product space. For any bounded subset such that the origin is in the exterior of (i.e., the complement is a neighborhood of ), and for any real exponent , the function is integrable on .
implies integrability of on when
Let be a positive natural number and be a -dimensional real inner product space. Let be a set such that its complement is a neighborhood of the origin (implying the origin is in the exterior of ). For any real number , if , then the function is integrable on .
