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Physlib.SpaceAndTime.Space.Derivatives.Basic

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definition

Spatial derivative in direction μ\mu

#deriv

Given a function f:Space dMf: \text{Space } d \to M, where MM is a real topological vector space, and a basis index μ{0,,d1}\mu \in \{0, \dots, d-1\}, the spatial derivative is the function that maps each point xSpace dx \in \text{Space } d to the Fréchet derivative of ff at xx evaluated in the direction of the μ\mu-th standard basis vector eμe_\mu. This definition corresponds to the partial derivative of ff with respect to the μ\mu-th coordinate, denoted as fxμ\frac{\partial f}{\partial x_\mu} or μf\partial_\mu f.

definition

Spatial derivative notation [i]\partial[i]

#term∂[_]

This definition introduces the mathematical notation [i]\partial[i] as a shorthand for the spatial derivative operator `Space.deriv` in the direction of the ii-th basis vector. Given a function f:Space dMf: \text{Space } d \to M and an index i{0,,d1}i \in \{0, \dots, d-1\}, the expression [i]f\partial[i] f denotes the partial derivative of ff with respect to the ii-th coordinate direction.

theorem

deriv μf(x)=Df(x)(eμ)\text{deriv } \mu \, f(x) = \text{D}f(x)(e_\mu)

#deriv_eq

Let MM be a real topological vector space and f:Space dMf: \text{Space } d \to M be a function. For any basis index μ{0,,d1}\mu \in \{0, \dots, d-1\} and any point xSpace dx \in \text{Space } d, the spatial derivative of ff at xx in the direction of the μ\mu-th standard basis vector is equal to the Fréchet derivative of ff at xx evaluated at the μ\mu-th basis vector eμe_\mu: \[ \text{deriv } \mu \, f(x) = \text{D}f(x)(e_\mu) \] where Df(x)\text{D}f(x) denotes the Fréchet derivative of ff at xx, and eμe_\mu is the μ\mu-th vector of the standard orthonormal basis of Space d\text{Space } d.

theorem

μf=λx,Df(x)eμ\partial_\mu f = \lambda x, Df(x) \cdot e_\mu

#deriv_eq_fderiv_fun

Let MM be a real topological vector space and f:Space dMf: \text{Space } d \to M be a function. For any index μ{0,,d1}\mu \in \{0, \dots, d-1\}, the spatial derivative μf\partial_\mu f is the function that maps each point xSpace dx \in \text{Space } d to the Fréchet derivative of ff at xx evaluated in the direction of the μ\mu-th standard basis vector eμe_\mu. Mathematically, μf=λx,Df(x)eμ\partial_\mu f = \lambda x, Df(x) \cdot e_\mu, where Df(x)Df(x) denotes the Fréchet derivative of ff at xx and eμe_\mu is the μ\mu-th standard orthonormal basis vector of Space d\text{Space } d.

theorem

μf(x)=Df(x)(eμ)\partial_\mu f(x) = Df(x)(e_\mu)

#deriv_eq_fderiv_basis

Let MM be a real topological vector space and f:Space dMf: \text{Space } d \to M be a function. For any point xSpace dx \in \text{Space } d and any basis index μ{0,,d1}\mu \in \{0, \dots, d-1\}, the spatial derivative of ff in the direction μ\mu at xx, denoted μf(x)\partial_\mu f(x), is equal to the Fréchet derivative of ff at xx evaluated at the μ\mu-th standard basis vector eμe_\mu.

theorem

Fréchet Derivative as a Sum of Spatial Derivatives: Df(x)y=iyiif(x)Df(x)y = \sum_i y_i \partial_i f(x)

#fderiv_eq_sum_deriv

Let MM be a real topological vector space and f:Space dMf: \text{Space } d \to M be a function. For any points x,ySpace dx, y \in \text{Space } d, the Fréchet derivative of ff at xx evaluated in the direction yy, denoted Df(x)(y)Df(x)(y), is equal to the sum over all basis indices i{0,,d1}i \in \{0, \dots, d-1\} of the ii-th coordinate of yy scaled by the spatial derivative of ff at xx in the ii-th direction: \[ Df(x)(y) = \sum_{i=0}^{d-1} y_i \cdot \partial_i f(x) \] where yiy_i is the ii-th component of yy and if(x)\partial_i f(x) is the partial derivative of ff at xx with respect to the ii-th standard basis vector.

theorem

μf(x)=(df)x(eμ)\partial_\mu f(x) = (df)_x(e_\mu)

#deriv_eq_mfderiv

Let MM be a real normed space and f:Space dMf: \text{Space } d \to M be a function. For any point xSpace dx \in \text{Space } d and any basis index μ{0,,d1}\mu \in \{0, \dots, d-1\}, the spatial derivative of ff in the direction μ\mu at xx, denoted μf(x)\partial_\mu f(x), is equal to the manifold derivative of ff at xx (with respect to the standard model spaces Rd\mathbb{R}^d and MM) evaluated at the μ\mu-th standard basis vector eμe_\mu.

theorem

Equivalence of Manifold and Fréchet Differentiability on Space d\text{Space } d

#mdifferentiable_manifoldStructure_iff_differentiable

Let dd be a dimension and MM be a real normed vector space. For a function f:Space dMf : \text{Space } d \to M and a point xSpace dx \in \text{Space } d, ff is manifold-differentiable at xx with respect to the specific manifold structure `manifoldStructure d` on the domain and the canonical manifold structure I(R,M)\mathcal{I}(\mathbb{R}, M) on the codomain if and only if ff is Fréchet differentiable at xx in the standard sense of real normed spaces.

theorem

μf(x)\partial_\mu f(x) equals the manifold derivative of ff under `manifoldStructure`

#deriv_eq_mfderiv_manifoldStructure

Let MM be a real normed space and f:Space dMf: \text{Space } d \to M be a function. For any point xSpace dx \in \text{Space } d and any coordinate index μ{0,,d1}\mu \in \{0, \dots, d-1\}, the spatial derivative of ff at xx in the direction μ\mu is equal to the manifold Fréchet derivative of ff at xx applied to the μ\mu-th standard basis vector eμRde_\mu \in \mathbb{R}^d. This derivative is taken with respect to the specific manifold structure `Space.manifoldStructure d` on the domain and the canonical manifold structure I(R,M)\mathcal{I}(\mathbb{R}, M) on the codomain. Mathematically: \[ \text{deriv } \mu \, f(x) = (df)_x(e_\mu) \] where (df)x(df)_x is the manifold derivative at xx, and eμe_\mu is the vector in the Euclidean space Rd\mathbb{R}^d with 11 at the μ\mu-th coordinate and 00 elsewhere.

theorem

μ(constant)=0\partial_\mu (\text{constant}) = 0

#deriv_const

Let MM be a real normed space and dd be a natural number representing the dimension of the domain Space d\text{Space } d. For any constant value mMm \in M and any basis index μ{0,,d1}\mu \in \{0, \dots, d-1\}, let f:Space dMf: \text{Space } d \to M be the constant function f(x)=mf(x) = m. The spatial derivative of ff in the direction of the μ\mu-th basis vector at any point tSpace dt \in \text{Space } d is zero, denoted as μf(t)=0\partial_\mu f(t) = 0.

theorem

u(f1+f2)=uf1+uf2\partial_u (f_1 + f_2) = \partial_u f_1 + \partial_u f_2

#deriv_add

Let MM be a real normed space and dd be a natural number. Let f1,f2:Space dMf_1, f_2: \text{Space } d \to M be two functions that are differentiable on Space d\text{Space } d. For any basis index u{0,,d1}u \in \{0, \dots, d-1\}, the spatial derivative of the sum of the functions is equal to the sum of their individual spatial derivatives: \[ \partial_u (f_1 + f_2) = \partial_u f_1 + \partial_u f_2 \] where u\partial_u denotes the partial derivative with respect to the uu-th coordinate (the Fréchet derivative evaluated in the direction of the uu-th standard basis vector).

theorem

u(f1,i+f2,i)=uf1,i+uf2,i\partial_u (f_{1,i} + f_{2,i}) = \partial_u f_{1,i} + \partial_u f_{2,i}

#deriv_coord_add

Let f1,f2:Space dRdf_1, f_2: \text{Space } d \to \mathbb{R}^d be two differentiable functions. For any basis index u{0,,d1}u \in \{0, \dots, d-1\} of the domain and any coordinate index ii of the codomain Rd\mathbb{R}^d, the spatial derivative u\partial_u of the sum of the ii-th components of f1f_1 and f2f_2 is equal to the sum of the spatial derivatives of the individual ii-th components: \[ \partial_u (f_1(x)_i + f_2(x)_i) = \partial_u (f_1(x)_i) + \partial_u (f_2(x)_i) \] where f(x)if(x)_i denotes the ii-th component of the vector f(x)f(x).

theorem

Product rule for spatial derivatives: u(cf)=cuf+ucf\partial_u (c \cdot f) = c \cdot \partial_u f + \partial_u c \cdot f

#deriv_smul

Let MM be a real normed space and k\mathbb{k} be a normed algebra over R\mathbb{R}. For functions c:Space dkc: \text{Space } d \to \mathbb{k} and f:Space dMf: \text{Space } d \to M that are differentiable at a point xSpace dx \in \text{Space } d, the spatial derivative in direction u{0,,d1}u \in \{0, \dots, d-1\} of their scalar product satisfies the Leibniz rule: \[ \partial_u (c \cdot f)(x) = c(x) \cdot \partial_u f(x) + (\partial_u c(x)) \cdot f(x) \] where u\partial_u denotes the partial derivative with respect to the uu-th standard basis vector.

theorem

u(cf)=cuf\partial_u (c \cdot f) = c \cdot \partial_u f

#deriv_const_smul

Let MM be a real normed space and RR be a semiring acting on MM (such that the action commutes with the real scalar multiplication and constant scalar multiplication is continuous). Let f:Space dMf: \text{Space } d \to M be a differentiable function and cRc \in R be a constant. For any index u{0,,d1}u \in \{0, \dots, d-1\}, the spatial derivative in direction uu (denoted by u\partial_u) satisfies: \[ \partial_u (c \cdot f) = c \cdot \partial_u f \] where uf\partial_u f is the derivative of ff in the direction of the uu-th standard orthonormal basis vector of Space d\text{Space } d.

theorem

u(kfi)=kufi\partial_u (k f_i) = k \partial_u f_i

#deriv_coord_smul

Let f:Space dRdf: \text{Space } d \to \mathbb{R}^d be a differentiable function and kRk \in \mathbb{R} be a scalar constant. For any point xSpace dx \in \text{Space } d, coordinate index i{0,,d1}i \in \{0, \dots, d-1\}, and basis index u{0,,d1}u \in \{0, \dots, d-1\}, the spatial derivative in direction uu (denoted by u\partial_u) of the ii-th component of ff scaled by kk satisfies: \[ \partial_u (x \mapsto k \cdot f_i(x)) = k \cdot \partial_u f_i(x) \] where fi(x)f_i(x) denotes the ii-th coordinate of the vector f(x)f(x).

theorem

Commutativity of spatial derivatives: uvf=vuf\partial_u \partial_v f = \partial_v \partial_u f for C2C^2 functions

#deriv_commute

Let MM be a real normed space and f:Space dMf: \text{Space } d \to M be a function. If ff is twice continuously differentiable (of class C2C^2), then for any indices u,v{0,,d1}u, v \in \{0, \dots, d-1\}, the spatial derivatives in those directions commute: \[ \partial_u (\partial_v f) = \partial_v (\partial_u f) \] where μf\partial_\mu f denotes the derivative of ff in the direction of the μ\mu-th standard orthonormal basis vector of Space d\text{Space } d.

theorem

μxμ=1\partial_\mu x_\mu = 1

#deriv_component_same

For any dimension dd, given an index μ{0,,d1}\mu \in \{0, \dots, d-1\} and a point xx in the space Space d\text{Space } d, the spatial derivative of the μ\mu-th coordinate function f(x)=xμf(x) = x_\mu in the direction of the μ\mu-th standard basis vector is equal to 1: \[ \partial_\mu (x \mapsto x_\mu) = 1 \] where xμx_\mu denotes the μ\mu-th component of the vector xx.

theorem

μxν=0\partial_\mu x_\nu = 0 for μν\mu \neq \nu in Space d\text{Space } d

#deriv_component_diff

For a given dimension dd, let μ\mu and ν\nu be distinct indices in {0,1,,d1}\{0, 1, \dots, d-1\} (i.e., μν\mu \neq \nu). For any point xx in Space d\text{Space } d, the spatial derivative of the ν\nu-th coordinate function with respect to the μ\mu-th direction is zero: \[ \partial_\mu (x \mapsto x_\nu) = 0 \] where xνx_\nu denotes the ν\nu-th component of xx, and μ\partial_\mu denotes the derivative in the direction of the μ\mu-th standard orthonormal basis vector eμe_\mu.

theorem

νxμ=δνμ\partial_\nu x_\mu = \delta_{\nu\mu}

#deriv_component

For a given dimension dd, let μ\mu and ν\nu be indices in {0,1,,d1}\{0, 1, \dots, d-1\}. For any point xx in Space d\text{Space } d, the spatial derivative of the μ\mu-th coordinate function with respect to the ν\nu-th direction is given by: \[ \partial_\nu (x \mapsto x_\mu) = \begin{cases} 1 & \text{if } \nu = \mu \\ 0 & \text{if } \nu \neq \mu \end{cases} \] where xμx_\mu denotes the μ\mu-th component of the vector xx, and ν\partial_\nu denotes the derivative in the direction of the ν\nu-th standard basis vector.

theorem

ν(xμ2)=2xμδνμ\partial_\nu (x_\mu^2) = 2x_\mu \delta_{\nu\mu}

#deriv_component_sq

In a dd-dimensional space Space d\text{Space } d, let μ\mu and ν\nu be indices in {0,1,,d1}\{0, 1, \dots, d-1\}. For any point xSpace dx \in \text{Space } d, the spatial derivative of the square of the μ\mu-th coordinate function in the direction of the ν\nu-th standard basis vector is given by: \[ \partial_\nu (x \mapsto x_\mu^2) = \begin{cases} 2x_\mu & \text{if } \nu = \mu \\ 0 & \text{if } \nu \neq \mu \end{cases} \] where xμx_\mu denotes the μ\mu-th component of the vector xx, and ν\partial_\nu denotes the derivative evaluated in the direction of the ν\nu-th standard basis vector eνe_\nu.

theorem

ν(fμ)=(νf)μ\partial_\nu (f_\mu) = (\partial_\nu f)_\mu for Euclidean-valued functions

#deriv_euclid

Let f:Space dRnf: \text{Space } d \to \mathbb{R}^n be a differentiable function, where the codomain is the nn-dimensional Euclidean space. For any point xSpace dx \in \text{Space } d, any domain basis index ν{0,,d1}\nu \in \{0, \dots, d-1\}, and any codomain component index μ{0,,n1}\mu \in \{0, \dots, n-1\}, the spatial derivative of the μ\mu-th component of ff in the direction ν\nu is equal to the μ\mu-th component of the spatial derivative of ff in the direction ν\nu. That is, \[ \partial_\nu (x \mapsto f(x)_\mu) = (\partial_\nu f)_\mu \]

theorem

ν(fμ)=(νf)μ\partial_\nu (f_\mu) = (\partial_\nu f)_\mu for Lorentz-valued functions

#deriv_lorentz_vector

Let f:Space dLorentz.Vector df: \text{Space } d \to \text{Lorentz.Vector } d be a differentiable function. For any spatial coordinate index ν{0,,d1}\nu \in \{0, \dots, d-1\} and any Lorentz vector component index μ\mu, the spatial derivative of the μ\mu-th component of ff at a point xx is equal to the μ\mu-th component of the spatial derivative of ff at xx. Mathematically, ν(fμ)(x)=(νf(x))μ\partial_\nu (f_\mu)(x) = (\partial_\nu f(x))_\mu where ν\partial_\nu denotes the derivative with respect to the ν\nu-th standard basis vector of Space d\text{Space } d.

theorem

xx2x \mapsto \|x\|^2 is differentiable on Space d\text{Space } d

#norm_sq_differentiable

In the dd-dimensional real vector space Space d\text{Space } d, the function mapping each element xx to the square of its Euclidean norm, xx2x \mapsto \|x\|^2, is differentiable over R\mathbb{R}.

theorem

i(x2)=2xi\partial_i (\|x\|^2) = 2x_i

#deriv_norm_sq

In the dd-dimensional real inner product space Space d\text{Space } d, for any point xSpace dx \in \text{Space } d and any basis index i{0,1,,d1}i \in \{0, 1, \dots, d-1\}, the spatial derivative of the squared Euclidean norm function xx2x \mapsto \|x\|^2 in the direction of the ii-th basis vector at xx is equal to 2xi2x_i. Mathematically, \[ \partial_i (\|x\|^2) = 2x_i \] where xix_i denotes the ii-th component of the vector xx, and i\partial_i denotes the spatial derivative in the direction of the ii-th standard basis vector eie_i.

theorem

yy,yy \mapsto \langle y, y \rangle is Differentiable on Space d\text{Space } d

#inner_differentiable

For any dimension dNd \in \mathbb{N}, the function yy,yy \mapsto \langle y, y \rangle mapping an element of the dd-dimensional real inner product space Space d\text{Space } d to its inner product with itself is differentiable over the real numbers R\mathbb{R}.

theorem

yy,yy \mapsto \langle y, y \rangle is Differentiable at xx

#inner_differentiableAt

For any dimension dNd \in \mathbb{N} and any element xx of the dd-dimensional real inner product space Space d\text{Space } d, the function mapping ySpace dy \in \text{Space } d to the inner product y,y\langle y, y \rangle is differentiable at xx over the real numbers R\mathbb{R}.

theorem

Differentiability of f,g\langle f, g \rangle at xx

#inner_apply_differentiableAt

Let MM be a real normed space and dd be a natural number. Suppose f,g:MSpace df, g: M \to \text{Space } d are functions. If ff and gg are differentiable at a point xMx \in M, then the scalar-valued function mapping yMy \in M to the inner product f(y),g(y)\langle f(y), g(y) \rangle is differentiable at xx.

theorem

The inner product of differentiable functions on Space dd is differentiable

#inner_apply_differentiable

Let MM be a real normed space and dd be a natural number. If the functions f:MSpace df: M \to \text{Space } d and g:MSpace dg: M \to \text{Space } d are differentiable, then the function mapping each yMy \in M to the inner product f(y),g(y)\langle f(y), g(y) \rangle is also differentiable.

theorem

The function yy,yy \mapsto \langle y, y \rangle is CnC^n on Space d\text{Space } d

#inner_contDiff

For any dimension dd and any nN{}n \in \mathbb{N} \cup \{\infty\}, the function on the dd-dimensional space Space d\text{Space } d that maps a vector yy to its inner product with itself, y,y=i=1dyi2\langle y, y \rangle = \sum_{i=1}^d y_i^2, is nn-times continuously differentiable (CnC^n) over the real numbers R\mathbb{R}.

theorem

The inner product of two CnC^n functions is CnC^n

#inner_apply_contDiff

Let MM be a real normed vector space and dd be a natural number. Let Space d\text{Space } d denote the dd-dimensional real inner product space where the inner product of two vectors p,qp, q is given by p,q=ipiqi\langle p, q \rangle = \sum_{i} p_i q_i. If f:MSpace df: M \to \text{Space } d and g:MSpace dg: M \to \text{Space } d are nn-times continuously differentiable functions (of class CnC^n) for nN{}n \in \mathbb{N} \cup \{\infty\}, then the mapping yf(y),g(y)y \mapsto \langle f(y), g(y) \rangle is also an nn-times continuously differentiable function from MM to R\mathbb{R}.

theorem

ix,x=2xi\partial_i \langle x, x \rangle = 2x_i

#deriv_eq_inner_self

In the dd-dimensional real inner product space Space d\text{Space } d, for any point xx and any basis index i{0,1,,d1}i \in \{0, 1, \dots, d-1\}, the spatial derivative of the function xx,xx \mapsto \langle x, x \rangle in the direction of the ii-th standard basis vector at xx is equal to 2xi2x_i. Mathematically, \[ \partial_i \langle x, x \rangle = 2x_i \] where ,\langle \cdot, \cdot \rangle denotes the real inner product and xix_i denotes the ii-th component of the vector xx.

theorem

ix,x2=(x2)i\partial_i \langle x, x_2 \rangle = (x_2)_i

#deriv_inner_left

For any dimension dd, let x1x_1 and x2x_2 be vectors in the dd-dimensional real inner product space Space d\text{Space } d. For any basis index i{0,,d1}i \in \{0, \dots, d-1\}, the spatial derivative of the function f(x)=x,x2f(x) = \langle x, x_2 \rangle in the direction of the ii-th standard basis vector, evaluated at the point x1x_1, is equal to the ii-th component of x2x_2: i(x,x2)x=x1=(x2)i\partial_i (\langle x, x_2 \rangle)|_{x=x_1} = (x_2)_i

theorem

ix1,x=(x1)i\partial_i \langle x_1, x \rangle = (x_1)_i

#deriv_inner_right

Let Space d\text{Space } d be a dd-dimensional real inner product space. For any vectors x1,x2Space dx_1, x_2 \in \text{Space } d and any basis index i{0,,d1}i \in \{0, \dots, d-1\}, let f:Space dRf: \text{Space } d \to \mathbb{R} be the function defined by f(x)=x1,xf(x) = \langle x_1, x \rangle. The spatial derivative of ff in the direction of the ii-th standard basis vector at the point x2x_2 is equal to the ii-th component of x1x_1: i(x1,x)x=x2=(x1)i\partial_i (\langle x_1, x \rangle)|_{x=x_2} = (x_1)_i

theorem

The Partial Derivative of a C2C^2 Function is Differentiable

#deriv_differentiable

Let MM be a real normed space and f:Space dMf: \text{Space } d \to M be a function. If ff is twice continuously differentiable (C2C^2), then for any index i{0,,d1}i \in \{0, \dots, d-1\}, the spatial derivative if\partial_i f is differentiable. Here, if\partial_i f denotes the partial derivative of ff in the direction of the ii-th standard basis vector of Space d\text{Space } d.

theorem

If ff is Cn+1C^{n+1}, then f\nabla f is CnC^n

#deriv_contDiff

Let f:Space dRf: \text{Space } d \to \mathbb{R} be a function. If ff is continuously differentiable of order n+1n+1 (Cn+1C^{n+1}), then the function that maps each point xSpace dx \in \text{Space } d to the collection of its spatial partial derivatives (if(x))i=0d1(\partial_i f(x))_{i=0}^{d-1} is continuously differentiable of order nn (CnC^n). Here, Space d\text{Space } d is a dd-dimensional real inner product space, and if\partial_i f denotes the derivative of ff in the direction of the ii-th vector of the standard orthonormal basis.

definition

Distributional partial derivative μ\partial_\mu on Space d\text{Space } d

#distDeriv

Let Space d\text{Space } d be a dd-dimensional real inner product space and MM be a real normed vector space. Given an index μ{0,1,,d1}\mu \in \{0, 1, \dots, d-1\}, the operator distDeriv μ\text{distDeriv } \mu is an R\mathbb{R}-linear map that sends a distribution f:Space dd[R]Mf: \text{Space } d \to d[\mathbb{R}] M to its partial derivative in the direction of the μ\mu-th standard basis vector eμe_\mu. This derivative is defined by composing the distributional Fréchet derivative DfDf with the evaluation map at eμe_\mu, representing the directional derivative μf\partial_\mu f.

theorem

(μf)(ϵ)=(Df)(ϵ)(eμ)(\partial_\mu f)(\epsilon) = (Df)(\epsilon)(e_\mu) for distributions

#distDeriv_apply

Let Space d\text{Space } d be a dd-dimensional real inner product space and MM be a real normed vector space. Let {e0,e1,,ed1}\{e_0, e_1, \dots, e_{d-1}\} be the standard orthonormal basis of Space d\text{Space } d. For a distribution f:Space dd[R]Mf : \text{Space } d \to d[\mathbb{R}] M, an index μ{0,1,,d1}\mu \in \{0, 1, \dots, d-1\}, and a Schwartz test function ϵS(Space d,R)\epsilon \in \mathcal{S}(\text{Space } d, \mathbb{R}), the evaluation of the distributional partial derivative μf\partial_\mu f at ϵ\epsilon is equal to the distributional Fréchet derivative DfDf evaluated at ϵ\epsilon and applied to the basis vector eμe_\mu: \[ (\partial_\mu f)(\epsilon) = (Df)(\epsilon)(e_\mu) \]

theorem

μνη=νμη\partial_\mu \partial_\nu \eta = \partial_\nu \partial_\mu \eta for Schwartz Functions

#schwartMap_fderiv_comm

For a Schwartz function ηS(Space d,R)\eta \in \mathcal{S}(\text{Space } d, \mathbb{R}) on a dd-dimensional real inner product space, let {ei}\{e_i\} be the standard orthonormal basis of Space d\text{Space } d. For any point xSpace dx \in \text{Space } d and any indices μ,ν{0,,d1}\mu, \nu \in \{0, \dots, d-1\}, the mixed partial derivatives of η\eta commute: \[ \partial_\mu (\partial_\nu \eta)(x) = \partial_\nu (\partial_\mu \eta)(x) \] where i\partial_i denotes the directional derivative in the direction of the ii-th basis vector eie_i.

theorem

Commutativity of Distributional Partial Derivatives μνf=νμf\partial_\mu \partial_\nu f = \partial_\nu \partial_\mu f

#distDeriv_commute

Let Space d\text{Space } d be a dd-dimensional real inner product space and MM be a real normed vector space. For any MM-valued distribution f:Space dd[R]Mf: \text{Space } d \to d[\mathbb{R}] M and any indices μ,ν{0,1,,d1}\mu, \nu \in \{0, 1, \dots, d-1\}, the distributional partial derivatives with respect to the standard basis vectors commute: \[ \partial_\nu (\partial_\mu f) = \partial_\mu (\partial_\nu f) \] where i\partial_i denotes the operator `distDeriv i` acting on the space of distributions.