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Physlib.QuantumMechanics.HilbertSpaces.SpaceD.MomentumStates

Momentum states

i. Overview

Informally, the momentum "state" corresponding to momentum `p` is the non-normalizable plane wave `exp (I p ⬝ᵥ x)`. More precisely, the momentum "state" lives in the _rigged_ Hilbert space `𝓢(Space d, ℂ) < SpaceDHilbertSpace d μ < StrongDual ℂ 𝓢(Space d, ℂ)` as the element of the dual of `𝓢(Space d, ℂ)` defined by evaluation of the Fourier transform at `p`.

ii. Key results

iii. Table of contents

iv. References

  • https://en.wikipedia.org/wiki/Rigged_Hilbert_space

2 declarations

definition

Momentum state p|p\rangle as a tempered distribution

For a given momentum vector pSpace dp \in \text{Space } d (where Space d\text{Space } d is a dd-dimensional real inner product space), the momentum state is defined as a tempered distribution in the strong dual of the Schwartz space S(Space d,C)\mathcal{S}(\text{Space } d, \mathbb{C}). Formally, it is the composition of the continuous linear Fourier transform F\mathcal{F} and the Dirac delta distribution δ\delta centered at (2π)1p(2\pi)^{-1}p. For any test function ψS(Space d,C)\psi \in \mathcal{S}(\text{Space } d, \mathbb{C}), the momentum state maps ψ\psi to the value of its Fourier transform at the point (2π)1p(2\pi)^{-1}p, which corresponds to the integral against the non-normalizable plane wave xeipxx \mapsto e^{i p \cdot x}.

theorem

The momentum state p|p\rangle evaluates ψ\psi as Fψ(p2π)\mathcal{F}\psi\left(\frac{p}{2\pi}\right)

For any momentum vector pSpace dp \in \text{Space } d and any test function ψ\psi in the Schwartz space S(Space d,C)\mathcal{S}(\text{Space } d, \mathbb{C}), the evaluation of the momentum state distribution p|p\rangle on ψ\psi is equal to the value of the Fourier transform of ψ\psi (denoted Fψ\mathcal{F}\psi) at the point 12πp\frac{1}{2\pi}p. Mathematically, this is expressed as: p,ψ=Fψ(12πp) \langle p, \psi \rangle = \mathcal{F}\psi\left(\frac{1}{2\pi} p\right)