Physlib

Physlib.QFT.QED.AnomalyCancellation.BasisLinear

Basis of `LinSols`

We give a basis of vector space `LinSols`, and find the rank thereof.

9 declarations

definition

jj-th basis charge vector for linear U(1)U(1) ACC solutions

For a pure U(1)U(1) gauge theory with n+1n+1 fermions, the function assigns to each index j∈{0,1,…,n−1}j \in \{0, 1, \dots, n-1\} a charge vector x∈Qn+1x \in \mathbb{Q}^{n+1}. This vector is defined such that its jj-th component is 11, its last component (at index nn) is −1-1, and all other components are 00. Mathematically, the components xix_i of the vector are: xi={1if i=j−1if i=n0otherwise x_i = \begin{cases} 1 & \text{if } i = j \\ -1 & \text{if } i = n \\ 0 & \text{otherwise} \end{cases} for i∈{0,1,…,n}i \in \{0, 1, \dots, n\}. These vectors form a basis for the space of solutions to the linear anomaly cancellation condition ∑i=0nxi=0\sum_{i=0}^n x_i = 0.

theorem

The jj-th component of the basis vector x(j)x^{(j)} is 11

For a pure U(1)U(1) gauge theory with n+1n+1 fermions, let x(j)∈Qn+1x^{(j)} \in \mathbb{Q}^{n+1} be the jj-th basis charge vector for the linear anomaly cancellation conditions, where j∈{0,…,n−1}j \in \{0, \dots, n-1\}. Then the jj-th component of the vector x(j)x^{(j)} is equal to 11.

theorem

xj(k)=0x^{(k)}_j = 0 for k≠jk \neq j and j<nj < n

Consider a pure U(1)U(1) gauge theory with n+1n+1 fermions. Let x(k)∈Qn+1x^{(k)} \in \mathbb{Q}^{n+1} be the kk-th basis charge vector for the space of solutions to the linear anomaly cancellation condition, where k∈{0,1,…,n−1}k \in \{0, 1, \dots, n-1\}. For any index j∈{0,1,…,n−1}j \in \{0, 1, \dots, n-1\} such that k≠jk \neq j, the jj-th component of the vector x(k)x^{(k)} is 00.

definition

jj-th basis vector for the linear solution space LinSols\text{LinSols} of pure U(1)U(1) theory

For a pure U(1)U(1) gauge theory with n+1n+1 fermions, this function assigns to each index j∈{0,1,…,n−1}j \in \{0, 1, \dots, n-1\} a charge vector that satisfies the linear anomaly cancellation condition (ACC). This vector is an element of the space LinSols\text{LinSols}, and its components xi∈Qx_i \in \mathbb{Q} are given by: xi={1if i=j−1if i=n0otherwise x_i = \begin{cases} 1 & \text{if } i = j \\ -1 & \text{if } i = n \\ 0 & \text{otherwise} \end{cases} for i∈{0,1,…,n}i \in \{0, 1, \dots, n\}. These vectors form a basis for the subspace of solutions to the gravitational anomaly condition ∑i=0nxi=0\sum_{i=0}^n x_i = 0.

theorem

(∑fi)j=∑(fi)j\left( \sum f_i \right)_j = \sum (f_i)_j for linear ACC solutions

Consider a pure U(1)U(1) gauge theory with nn fermions. Let f1,…,fkf_1, \dots, f_k be a collection of charge vectors in Qn\mathbb{Q}^n that satisfy the linear anomaly cancellation condition (ACC) ∑l=1n(fi)l=0\sum_{l=1}^n (f_i)_l = 0. For any fermion index j∈{1,…,n}j \in \{1, \dots, n\}, the jj-th component of the sum of these solutions is equal to the sum of the jj-th components of each individual solution: (∑i=1kfi)j=∑i=1k(fi)j \left( \sum_{i=1}^k f_i \right)_j = \sum_{i=1}^k (f_i)_j

definition

Linear isomorphism LinSols≅Qn\text{LinSols} \cong \mathbb{Q}^n for pure U(1)U(1) theory with n+1n+1 fermions

For a pure U(1)U(1) gauge theory with n+1n+1 fermions, let LinSols⊆Qn+1\text{LinSols} \subseteq \mathbb{Q}^{n+1} be the vector space of charge vectors (x0,x1,…,xn)(x_0, x_1, \dots, x_n) satisfying the linear anomaly cancellation condition ∑i=0nxi=0\sum_{i=0}^n x_i = 0. This definition establishes a linear isomorphism Φ:LinSols≅Qn\Phi: \text{LinSols} \cong \mathbb{Q}^n which serves as the coordinate map for the basis of the solution space. The forward map Φ\Phi sends a solution vector to its first nn components: Φ(x0,x1,…,xn)=(x0,x1,…,xn−1) \Phi(x_0, x_1, \dots, x_n) = (x_0, x_1, \dots, x_{n-1}) The inverse map Φ−1:Qn→LinSols\Phi^{-1}: \mathbb{Q}^n \to \text{LinSols} reconstructs the full solution vector using the basis vectors bi∈LinSols\mathbf{b}_i \in \text{LinSols} (where bi\mathbf{b}_i has 11 at index ii, −1-1 at index nn, and 00 elsewhere) as follows: Φ−1(f)=∑i=0n−1fibi \Phi^{-1}(f) = \sum_{i=0}^{n-1} f_i \mathbf{b}_i

definition

Basis for LinSols\text{LinSols} of a pure U(1)U(1) theory with n+1n+1 fermions

For a pure U(1)U(1) gauge theory with n+1n+1 fermions, let LinSols\text{LinSols} be the vector space over Q\mathbb{Q} consisting of charge vectors (x0,x1,…,xn)∈Qn+1(x_0, x_1, \dots, x_n) \in \mathbb{Q}^{n+1} that satisfy the linear anomaly cancellation condition ∑i=0nxi=0\sum_{i=0}^n x_i = 0. This definition constructs a basis for LinSols\text{LinSols} indexed by Fin n={0,1,…,n−1}\text{Fin } n = \{0, 1, \dots, n-1\}. The basis is defined such that the coordinate representation (the `repr` map) of a solution vector corresponds to the map Φ:LinSols→Qn\Phi: \text{LinSols} \to \mathbb{Q}^n that extracts the first nn components of the vector.

instance

The space LinSols\text{LinSols} for a pure U(1)U(1) theory with n+1n+1 fermions is finite-dimensional over Q\mathbb{Q}

For a pure U(1)U(1) gauge theory with n+1n+1 Weyl fermions, the vector space of linear solutions to the Anomaly Cancellation Conditions (ACCs), denoted by LinSols\text{LinSols}, is a finite-dimensional module over the field of rational numbers Q\mathbb{Q}. The space LinSols\text{LinSols} consists of charge vectors (x0,x1,…,xn)∈Qn+1(x_0, x_1, \dots, x_n) \in \mathbb{Q}^{n+1} that satisfy the gravitational anomaly condition ∑i=0nxi=0\sum_{i=0}^n x_i = 0.

theorem

rank⁡(LinSols)=n\operatorname{rank}(\text{LinSols}) = n for a pure U(1)U(1) theory with n+1n+1 fermions

For a pure U(1)U(1) gauge theory with n+1n+1 Weyl fermions, let LinSols\text{LinSols} be the vector space over Q\mathbb{Q} consisting of charge vectors (x0,x1,…,xn)∈Qn+1(x_0, x_1, \dots, x_n) \in \mathbb{Q}^{n+1} that satisfy the linear anomaly cancellation condition ∑i=0nxi=0\sum_{i=0}^n x_i = 0. The dimension of this space over the rational numbers Q\mathbb{Q}, denoted by finrank⁡Q(LinSols)\operatorname{finrank}_{\mathbb{Q}}(\text{LinSols}), is equal to nn.